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OpenStudy (anonymous):
Factor completely. -2k - k³ - 3k² a) k(-k + 1)(k - 2) b) -k(k - 1)(k - 2) c) -k(k + 1)(k + 2)
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OpenStudy (apples):
\[-2k-k^3-3k^2 = -k \cdot (k^2 + 3k + 2) = -k \cdot (k + 1) \cdot (k + 2) \]
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