Question

Factor completely.

-2k - k³ - 3k²

a) k(-k + 1)(k - 2)
b) -k(k - 1)(k - 2)
c) -k(k + 1)(k + 2)

Answer 1

\[-2k-k^3-3k^2 = -k \cdot (k^2 + 3k + 2) = -k \cdot (k + 1) \cdot (k + 2) \]