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find fy (x,y)=x^y
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okay so: fy = derivative with respect to y..
let: a =f(x;y)= x^y a = x^y lna = lnx^y lna = ylnx
[1/a][da/dy] = lnx a = x^y da/dy = fy = a*lnx = x^y * lnx
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