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Mathematics 25 Online
OpenStudy (anonymous):

find fy (x,y)=x^y

OpenStudy (bahrom7893):

okay so: fy = derivative with respect to y..

OpenStudy (bahrom7893):

let: a =f(x;y)= x^y a = x^y lna = lnx^y lna = ylnx

OpenStudy (bahrom7893):

[1/a][da/dy] = lnx a = x^y da/dy = fy = a*lnx = x^y * lnx

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