Question

identify critical points 4x^4 - 16x^2 +17

Answer 1

When the derivative equals zero.

Answer 2

find the first derivative then set it equal to 0 to find the critical numbers

Answer 3

derivate is 16x^3 - 32x^2?

Answer 4

a little off
16x^3-32x

Answer 5

then 16x^2-32x=0
factor 16x out of both terms, then set each factor = 0

Answer 6

sorry mistyped

Answer 7

okay so i got root two. but that's only the max

Answer 8

16x(x-2)=0
16x=0, would also get you the other one, x = 0

Answer 9

i see thanks