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Simplify. n ^6 · n^ 5 ÷ n ^4 · n ^3 ÷ n ^2 · n
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\[(n^6n^5)/(n^4n^3)/(n^2n)=n^{11}/n^7/n^3=n^{11}(n^3/n^7)=n^{14}/n^7\] =\[n^{14-7}= n^7\]
remember\[a^ma^n=a^{m+n}, a^m/a^n=a^{m-n}\] basic exponent properties
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