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this is my problem. Consider the points A(-2,5), B(2,-3), C(8,0), and P(4,3). P is on the bisector of angle ABC. Write an equation of the line in the point-slope form that contains the bisector of ABC. What I don't understand is which 2 points I to plug into the Y2-Y1 over X2-X1 (if that makes sense) formula.
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ok i barely remember this stuff. but you should graph it. which i did. p lands on line AC so you would plug in (-2,5) and (8,0) into y2-y1=m(x2-x1) hope that helps at all
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