Question

2e^x-1=0

Answer 1

\[2e ^{x}-1=0\]

Answer 2

\[e^{i\pi} + 1 = 0\]

jk

\[2e^x = 1\]
\[e^x = 1/2\]
\[ln(e^x) = ln(1/2)\]
\[x = ln(1/2)= -.69314718\]

Do you understand what I just did?