Question

2 absolute value x+1 greater than or equal to 28

Answer 1

2|x+1|≥28
First divide by 2 to get"
|x+1|≥14
Next break it into two parts:
x+1≥14 or x+1≤-14
then solve each one separately:
x≥13 or x≤-15

Answer 2

so if I put it in interval notation would it be (-funny eight,-15,]([13,funny eight)

Answer 3

Right:
\[(-\infty,-15],[13,\infty)\]