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Mathematics 8 Online
OpenStudy (anonymous):

(4a-a^2-3)/(ac+a-c-a^2) how do you simplify this? :/

OpenStudy (anonymous):

rearrange (-a^2+4a-3)/ (-a^2 +a +ac -c)= -(a^2 -4a+3)/[ -a(a -1) +c(a-1)] => -[(a -1)(a-4)]/ [(a-1)(-a+c)] cross out (a-1)-> -(a-4)/(c-a)

OpenStudy (anonymous):

okay, but the answer is 3-a/c-a . thanks anyway! ;)

OpenStudy (anonymous):

Omg. whooops. theres some error. . i think u gave the right answer

OpenStudy (anonymous):

=> -[(a -1)(a-3)]/ [(a-1)(-a+c)] cross out (a-1)-> -(a-3)/(c-a )= -a +3/ c-a

OpenStudy (anonymous):

yeah.. thanks! i got it. :)

OpenStudy (anonymous):

not a problem

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