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Mathematics 14 Online
OpenStudy (anonymous):

x2 + 8x + 12 = 0

OpenStudy (anonymous):

x = -2; x = -6 x = -2; x = 6 x = 2; x = 6 x = 2; x = -6

OpenStudy (anonymous):

whichh one?

OpenStudy (anonymous):

x=-6,-2

OpenStudy (anonymous):

so your first one

OpenStudy (anonymous):

thanks!

OpenStudy (anonymous):

(x + 7) (x - 15) = 0

OpenStudy (anonymous):

The quadratic factors as (x+6)(x+2)=0 so the solutions are x=-6 or x=-2.

OpenStudy (anonymous):

x = -7; x = 15 x = -7 x = 15 x = 7; x = -15

OpenStudy (anonymous):

which one

OpenStudy (anonymous):

You need an equation first

OpenStudy (anonymous):

(x + 7) (x - 15) = 0

OpenStudy (anonymous):

same thing as above: x=-7 and x=15

OpenStudy (anonymous):

x=-7 or x=15...they're both solutions.

OpenStudy (anonymous):

x2 + 5x = 6 x = 1; x = -6 x = -1; x = -6 x = -1; x = 6 x = 1; x = 6

OpenStudy (anonymous):

x=-6,1 x=-6,x=-1

OpenStudy (anonymous):

A,B,C,D?

OpenStudy (anonymous):

Smitty - when you factor as ( )( ) = 0, it means either the first factor is zero, the second is zero or they're both zero. The equation's true then for those x-values that make a factor equal to zero. x2 + 5x - 6 =0 -> (x+6)(x-1)=0 so the answer is x = -6 or x = 1.

OpenStudy (anonymous):

x = -1; x = -6 B!

OpenStudy (anonymous):

x(x - 8) = 9 x = -1; x = 9 x = -1; x = -9 x = 1 x = 1; x = -9

OpenStudy (anonymous):

x=-1,9 A

OpenStudy (anonymous):

Smitty, you have to expand the left-hand side, subtract 9 from both sides and either factorize or complete the square or use the quadratic equation to figure out x.

OpenStudy (anonymous):

x2 - 4 = 0 x = 2; x = -2 x = -2 no solutions x = 2

OpenStudy (anonymous):

x = +2 or -2

OpenStudy (anonymous):

x=2

OpenStudy (anonymous):

(x + 6) (5x - 3) 5x2 - 27x - 18 5x2 + 30x - 18 5x2 + 27x - 18 5x2 + 27x + 18

OpenStudy (anonymous):

sorry accidently hit enter early x = 2, -2

OpenStudy (anonymous):

i got it wrong haha ohwell

OpenStudy (anonymous):

5x^2+27x-18

OpenStudy (anonymous):

x2 - 10x + 21 = 0 x = 3; x = -7 x = 3; x = 7 x = -3; x = 7 x = -3; x = -7

OpenStudy (anonymous):

x=3,7 B

OpenStudy (anonymous):

x2 - 4 = 0 x = 2; x = -2 x = 2 no solutions x = -2 9. Multiply the binomials: (3x + 4) (5x - 4) 15x2 + 8x - 16 15x2 + 8x + 16 15x2 + 20x - 16 15x2 - 8x - 16 10. Find the solution(s) for x: x2 + 7x + 10 = 0 x = -2; x = 5 x = 2; x = 5 x = 2; x = -5 x = -2; x = -5 Session Complete

OpenStudy (anonymous):

x2 - 4 = 0 x = 2; x = -2 x = 2 no solutions x = -2

OpenStudy (anonymous):

Ok well I can't do all of your hw for you. sorry

OpenStudy (anonymous):

just one more?

OpenStudy (anonymous):

Ok choose 1!

OpenStudy (anonymous):

what?

OpenStudy (anonymous):

thanks for all theeee help before

OpenStudy (anonymous):

I can do one more but only one more and no problem

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