Question

Evaluate (x + y)^0 for x = 4 and y = 3.

a) 0
b) 1
c) 2
d)7

Answer 1

remember order of operations: PEMDAS (Please Excuse My Dear Aunt Sally): Parentheses, Exponents, Multiplication/Division, Addition/Subtraction. So the first thing to do is what is inside the parentheses: (x+y) = (4+3) = 7. Next we do the exponent part: 7^0 = 1, because anything raised to the power 0 is 1.