The width of a rectangle is 8 inches less than one-half of its length. If the perimeter of the rectangle is 38 inches, find the area of the rectangle.

Question

anonymous · Answer

If the length is x, then the width would be (x/2-8)

Perimeter = x + x +(x/2-8) + (x/2-8)
38=2x +x -16

Solve for x and you get x = 18 inches.

Length = x = 18 inches
Width = (x/2-8) = 1 inches

Area of a rectangle is length times width

Area =$$18\times1$$=18 inches squared.