Question

Multiply:

8x^2 divide x^2 - 9 times x^2 + 6x + 9 divide 16x^3

Answer 1

\[\frac{8x^2}{x^2-9} \times \frac{x^2+6x+9}{16x^3}\] =\[\frac{8x^2}{(x-3)(x+3)} \times \frac{(x+3)^2}{16x^3}\]=\[\frac{x+3}{2x(x-3)}\]

Answer 2

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