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Divide: 3y + 12/8y^3 divide 9y + 36/16y^3
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16y^3 is divided by 36 only or whole?
36 over 16y^3
(9y+36/16y^3)/(3y+12/8y^3) =[(144y^4+36)/16y^3] / [(24y^4+12)/8y^3] =[36(4y^4+1)/16y^3] / [12(2y^4+1)/8y^3] =[3(4y^4+1)] / (2y^4+1) =12y^4+3/2y^4+1 =6-3/2y^4+1
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