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a coin is tossed five times in how many ways can one get exactly no heads? five heads?
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One can get no heads in exactly one way. We can see this as (5C0)=1 One can get 5 heads in exactly one way. We can see this as (5C5)=1
in how many ways can one get exactly one head? four heads?
Well, lets enumerate them: For one head: HTTTT, THTTT, TTHTT, TTTHT, TTTTH i.e. 5 ways This is equal to (5C1), that is the binomial coefficient or "choose" function. Now you try with 4 heads.
5c2
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