Question

9x^-6y^8
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18x^9y^2

Answer 1

so you have \[9x ^{-6y ^{6}}/ 18x ^{9y ^{2}}\]

so take it first by the coefficients 9/18 can be reduced to 1/2
then the exponents since the base is the same (x) we subtract
so -6y^2 - 9y^2 = -15y^2 so you end up with \[1/2x ^{15y ^{2}}\]
since the exponent was negative we dropped it to the denominator

Answer 2

thanks you

Answer 3

can u please help with my math question?
thanks so much