Question

I am currently using python version 2.5.4 and every time I try to use the "else" function it I get a syntax error. Why would I get this error? "SyntaxError: invalid syntax" Thanks in advance

Answer 1

Can you write out an example?

Answer 2

ok here is an example: I did create the problem myself but in every problem I write else: I always get this same response:
>>> limit = 1000
>>> counter = 1
>>> current_number = 1
>>> while counter < limit:
is_prime = 1
current_number = current_number + 2
for i in range (2, current_number%i) == 0:
is_prime = 0
break
if is_prime != 0:
counter = counter + 1
if counter == limit:
print current_number, "is the 1000th prime number"
else:

SyntaxError: invalid syntax

Answer 3

The else function is colored in red to show that there is a syntax error there.

Answer 4

Well, here the else: is tabbed incorrectly. It needs to be lined up with the if:

if is_prime != 0:
counter = counter + 1
if counter == limit:
print current_number, "is the 1000th prime number"
else:

Let me know if that solved it.

Answer 5

yes, that was the problem thanks for the help.