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Can anyone possibly show the formula how to solve this problem? Slope Intercept Form of the equation of a line that passes the point (3,-2) and had a slope of 1/3.
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Formula which you can use is \[y=mx+c\] where "m" is slope then put the point in the equation and get the value of c. \[c=y-mx\] where (x,y) is given point.
Sgadi, can you show where to plug in the point and steps how to solve this equation?
If slope is m and passes through point (p,q) then the equation is \[y=mx+(q-mp)\]
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