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I'm wondering. If y(x)=K for all integer x. Is y(x) also considered as bounded?
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K is a constant.
y(x) is bounded if\[y(x)\le M\]for all x in your domain and where M some constant. You have this condition:\[y(x)=K \rightarrow y(x)\le K\] (you can choose your constant M to be K).
That is, y(x) is bounded for all x an integer.
thanks..
No probs.
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