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Mathematics 52 Online
OpenStudy (anonymous):

Factor Completely: x cubed + 9x Squared+8x

OpenStudy (anonymous):

You have a common factor of x in each of those terms. You should start by factoring out x,\[x(x^2+9x+8)\]would be the first step. You can now look at the quadratic in the brackets and factor that...

OpenStudy (anonymous):

I don't know what method(s) for factoring quadratics you use, by something like cross method, sum and product, etc. will have the quadratic factor as\[(x+1)(x+8)\]So your final answer is \[x(x+1)(x+8)\]

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