Question

using implicit differentiation to find y' for 2y2-3x3-5=0 and evaluate at (x,y)=(1,2)

Answer 1

2y^2-3x^3-5=0
2ydy/dx-9x^2=0
2ydy/dx=9x^2
dy/dx=9x^2/2y
at (x,y)=(1,2)
y'=9^2/2(2)
=81/4

Answer 2

4yy'-9x^2=0

y'=9x^2/4y
@ (1,2) y' =9/8

Answer 3

thank you