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Mathematics 73 Online
OpenStudy (anonymous):

A rope is attached to a pulley with a weight attached to the end of the rope. What is the radius of the pulley if rotating the pulley 51.6 degrees lifts the weight 11.4 inches

OpenStudy (anonymous):

equate the arc length formula with the height lifted off the ground and solve for radius, be sure to convert degrees to radians

OpenStudy (anonymous):

Whata the formula look like

OpenStudy (anonymous):

s=r\[\theta\]

OpenStudy (anonymous):

What's s in the equation

OpenStudy (anonymous):

arc length

OpenStudy (anonymous):

There is no arc length. ???

OpenStudy (anonymous):

read my first post

OpenStudy (radar):

A full rotation would be 360 degrees. so 51.6 degrees would be a partial rotation. 51.6/360 would be the equivalent rotation. This partial rotation is equivalent to 11.4 inches of rotation. Other words a point on the circumference moved 11.4 inches.

OpenStudy (radar):

So 51/360 of a rotation is equal to 11.4, what would a full (1)rotation be equal to?

OpenStudy (radar):

From that we can conclude that .1433x=11.4 in. (51.6 degrees is 14% of 360degrees) x=81.42in.,or the circumference of pulley is 81.42in. C=pi D. D=C/pi=81.42/pi=25.9, radius would be D/2 or approx 12.9in

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