A rope is attached to a pulley with a weight attached to the end of the rope. What is the radius of the pulley if rotating the pulley 51.6 degrees lifts the weight 11.4 inches
equate the arc length formula with the height lifted off the ground and solve for radius, be sure to convert degrees to radians
Whata the formula look like
s=r\[\theta\]
What's s in the equation
arc length
There is no arc length. ???
read my first post
A full rotation would be 360 degrees. so 51.6 degrees would be a partial rotation. 51.6/360 would be the equivalent rotation. This partial rotation is equivalent to 11.4 inches of rotation. Other words a point on the circumference moved 11.4 inches.
So 51/360 of a rotation is equal to 11.4, what would a full (1)rotation be equal to?
From that we can conclude that .1433x=11.4 in. (51.6 degrees is 14% of 360degrees) x=81.42in.,or the circumference of pulley is 81.42in. C=pi D. D=C/pi=81.42/pi=25.9, radius would be D/2 or approx 12.9in
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