Question

2 cars started from the same point and traveled on a straight course in opposite directions for exactly 2hrs at which time they were 208 miles apart. If 1 car traveled on average 8 miles per hour faster than the other, what was the averag speed for each car for the 2hr trip?

Answer 1

If we let the slower car be traveling at x mph and the faster car be traveling at x+8, then we can figure out there speeds over 2 hours.

2(x+x+8)=208 -> x+x+8=104 -> 2x+8=104 -> 2x=96 -> x=48 mph.

48+(48+8) = 48 + 56 = 104 mph. 2 hrs * 104 miles = 208.

So, slow car = 48 mph; fast car = 56 mph