Question

If Leah is 6 years older than Sue, and John is 5 years older than Leah, and the total of their ages is 41. Then how old is Sue?

Answer 1

L= S+6 ; and J= 5+L; S+J+L=41.

S=L-6; J=5+L; L=L. To wit; (L-6)+(5+L)+L=41 ->3L-1=41 -> 3L=42.

L= 42/3 = 14

Leah is 14; Sue is 14-6 = 8; and John is 14+5=19. 14+8+19= 22+19 = 41

John should be moving out soon :)

Answer 2

Sue is 8.

Answer 3

take sue's age to be x.
Sue= x
Leah = x + 6 yrs old.
John = x + 6 +5 yrs old.
total = x + x + 6 + x + 6 + 5
=3x + 17
= 41 yrs old
3x = 41 - 17
= 24
x(Sue's age) = 24 / 3
= 8 yrs old.

i hope i helped u with your work :)