Find the equation of the line through the point (4, 7) that cuts off the least area from the first quadrant. Give your answer using the form below.
y - A = B(x - C)

A=
B=
C=

Question

Find the equation of the line through the point (4, 7) that cuts off the least area from the first quadrant. Give your answer using the form below.
y - A = B(x - C)

A=
B=
C=

amistre64 · Answer

would that be the area bound by the y-axis, x-axis, and a 45 degree line of negtive slope thru the point (4,7) ?

anonymous · Answer

I tried everything and all I get was wrong answers

amistre64 · Answer

Q1 is pretty large :)

amistre64 · Answer

what have you tried so far?

anonymous · Answer

Thank You for trying, I just called my friend, he is willing to show and teach me.

anonymous · Answer

A=7,B=7/4,C=4
y-7=7/4(x-4)
4(y-7)=7(x-4)
4y-28=7x-28
7x-4y=0