Question

Exponential equation help?
Solve: 3^2x+1=70

Answer 1

just to be clear the equation looks like this: \[3^{2x+1}=70\]

help solve please?

Answer 2

An easy way to solve this is using logarithms. If you take the \[\log_3(x)\] of both sides, you obtain: \[2x+1 = \log_3(70)\] Subtracting 1 and dividing by zero yields: \[(\log_3(70)-1)/2\] for your final answer