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Mathematics 13 Online
OpenStudy (anonymous):

if f(x)=sinx(cos-1),find f'(a)if a=pi*

OpenStudy (anonymous):

\[f'(x)=\sin{x}(-\sin{x})+\cos{x}(\cos{x}-1)\]\[=\cos^2{x}-\sin^2{x}-\cos{x}\]\[=\cos{2x}-\cos{x}\]Then,\[f'(\pi)=\cos{2\pi}-\cos{\pi}=1-(-1)=2\]

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