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find all the values of x which are solutions. A. x2 + 2= 27 B.-5|x| = -15
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B. \[-\left| x \right|=-15\]
messed up left off the 5.\[-5\left| x \right|=-15\]
\[\left| x \right|=-15\]
\[\left| x \right|=15\]
Please ignore the above last two entries.\[\left| x \right|=-15\div-5=3\]
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\[x=\pm3\]
Now for A.\[x ^{2}+2=27\] \[x ^{2}=27-2=25\] \[x=\sqrt{25}=\pm5\]
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