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Mathematics 23 Online
OpenStudy (anonymous):

(12y^3 + 9 y^2 + 21y) ÷ 3y Simplify with steps.

OpenStudy (vijay):

4Y^2+3Y+7

OpenStudy (anonymous):

\[{{12y^3+9y^2+21y}\over{3y}}\] Factor out a "y" \[{{y}\over{y}} \times {{12y^2+9y+21}\over{3}}\] Now lets factor out a "3" \[{{3}\over{3}} \times {{4y^2+3y+7}\over{1}}\] So our final answer is: \[4y^2+3y+7\]

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