Question

The perimeter of a rectanlge is 22 ft. The length is 7 ft longer than the width. Find the dimenisons. let x be length and y be width.

Answer 1

so 2x + 2y = 22
x = 7 + y
so 2(7 + y) + 2y = 22
14 + 4y = 22
y = 2
so x = 9

Answer 2

kool that is the way that i set it up but was worried thanks.

Answer 3

P = 2L + 2W
22=2(x+7)+2x
22=2x+14+2x
x=2 therefore L=9, W=2

Answer 4

Let x = length
w = width
x=w+7 (given)
2(w+7)+2w=22 (the sum of the four sides is the perimeter.
2w+14+2w=22
4w=22-14=8
w=2
x=w+7 (given)
x=9 so length =9 and width =2, Perimeter = 22, Length is 7 ft longer than width.
It all fits.