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find the derivative of F(x)=arctan sqrt(3x-1)
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\[(1/ 2x * \sqrt{3x-1})\]
i got stuck cuz i got 1/3x*1/2(3x-1)^-1/2
im confused
can u break this down to me
i dont understand how this is the answer
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i got 1/6x sqrt(3x-1)
i just need to know what step am i missing
vijay did u type somethin cause im not able to see what is being typed
u have differentiate inside the bracket, i mean 3x-1
so, u will 3 above, that 3 will be cut 6
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did u differentiate 3x-1 d(3x-1)/dx = 3
i dont understand because i thought i was supposed to differentiate sqrt (3x+1) which would be 1/2(3x+1)^-1/2
yes that that is correct, after this expression, u have to differentiate inside the sqrt .
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