Question

ok to find the derivative of f(x)=arctan(sqrt(3x-1)) i got all the way to 4/sqrt(-16x^2+8x)...that is wrong...what am i missing

Answer 1

\[[ 1 / (1 + 3x -1 )] * 2 *3 * 1/\sqrt{3x-1}\]

Answer 2

\[[ 1 / (1 + 3x -1 )] * 1/2 *3 * 1/\sqrt{3x-1}\]

Answer 3

sorry vijay i meant i got that answer for the other problem i just posted can u look at the other one i just posted

Answer 4

where did u post that ?

Answer 5

i just posted it

Answer 6

ooops,,,wrong problem...i meant i got that answer for f(x)=sin^-1(4x+1)

Answer 7

this is the problem that goes to the answer i got wrong