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Mathematics 15 Online
OpenStudy (anonymous):

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OpenStudy (anonymous):

∫[1,2,1/[(x+2)^2√((x+2)^2+16)],]=dx/u√(u^2+16)=[√(u^2+a^2)]/(a^2u) for u=x+2 and a=16

OpenStudy (anonymous):

\[y=3\chi ^{2}+\chi+1\]

OpenStudy (anonymous):

? how do you graph that?

OpenStudy (anonymous):

how do i solve this system: 5x+2y =7 -x/2 + y/6 = 3/2

OpenStudy (anonymous):

i used to know but I forgot sorry

OpenStudy (anonymous):

2+2=

OpenStudy (anonymous):

FISH!!!!!!

OpenStudy (anonymous):

In ∫ 2x(x^(2)+3)dx, if we let u=x^(2)+3,then 1.the integral form is u^(n)du and du=2x 2.the integral form u^(n)du cannot be used because n=1 3.the integral form is u^(n)du and du=2dx 4.the integral form is u^(n)du and du=2xd

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