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equation sets use digits:1 to 6 e.g.:6/3=5+2-4-1
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6(2)-3(1)=5+4
any?
\[(\sqrt{4})\div2=(5+3)-(6+1)\]
(5-2)/3=6-4-1 5*3=4*2+6+1 6*3=(5+4)*2*1 6+5=4*2+3+1
the last one should be 6+5=4*2 + 3*1
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* mean multiples right
yes
thank you so much :) can you read my another question
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