Question

Find the radius and the coordinates of the center of the circle X^2+Y^2+(6/5)X-(8/5)Y-8=0

Answer 1

This can be done by putting the x terms together and completing the square, and then putting the y terms together and completing the square.

Answer 2

If you get the problem in the form of
(x-h)^2 + (y-k)^2 = r^2, then (h,k) is the center and r is the radius.