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Mathematics 18 Online
OpenStudy (anonymous):

Find the numerical value of the expression: arccosh(1)=

OpenStudy (anonymous):

zero

OpenStudy (anonymous):

lol that was fast

OpenStudy (anonymous):

how did u do it?

OpenStudy (stacey):

cosh(t) = (e^t + e^-t)/2 Since we are looking for arccosh(1), we are looking for the value of t that makes cosh(t)=1.

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