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OpenStudy (anonymous):
Find the numerical value of the expression: arccosh(1)=
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OpenStudy (anonymous):
zero
OpenStudy (anonymous):
lol that was fast
OpenStudy (anonymous):
how did u do it?
OpenStudy (stacey):
cosh(t) = (e^t + e^-t)/2 Since we are looking for arccosh(1), we are looking for the value of t that makes cosh(t)=1.
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