Question

how to test absolute convergence of series

[(n+1)^n^2]
-----------
(n)^n^2

exponents are n squared, just to be clear

Answer 1

you can consider this example in geometric series type:
\[\sum_{?}^{?}((n+1)^2/n^2)^n\]
in geometric series if r^n is achieved and r=>1 then the serie is divergent.
In here (n+1)^2/n^2 is always bigger than 1 so it is divergent

bu arada Türksün demi lan:)