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Find all solutions of the equation. (Enter each answer in the form θ + 2πk, 0 ≤ θ < 2π. If there are any unused answer boxes, enter NONE in the last boxes.) 2cos^2(x)-cos(x)-1=0
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You can factor this expression.
i factored it to get (2cos(x) + 1)(cos(x) - 1) = 0
\[(2\cos(x)+1)(\cos(x)-1)=0\]
now set each factor equal to zero and solve for x
Cos(x)= -1/2 and Cos(x)= 1
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yes, but now you need to express all possible angles for which those ratios are correct
2pi/3, 4pi/3 and 2pi?
plus 2pik on all of them
yep
thank you!
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