Question

9^(2X)=(1/3)^(X+1)

Answer 1

\[\log9^{2x}=\log(\frac{1}{3})^{x+1}\rightarrow 2x.2\log3=(x+1)(-\log3)\]Expand and collect like terms and solve for x:\[x=-\frac{1}{5}\]

Answer 2

THANKS

Answer 3

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