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Mathematics 16 Online
OpenStudy (anonymous):

IS this factorable? x^4-6x^3+10x^2+2x-15

OpenStudy (anonymous):

I was able to factor it down to x(x^2+2)(x+6)(5x+1)+15

OpenStudy (anonymous):

(correction) x(x^2+2)(x+6)(5x+1)-15

OpenStudy (anonymous):

(eh, last correction...) x(x^2+2)(x-6)(5x+1)-15

OpenStudy (anonymous):

(x+1)(x-3)(x^2-4x+5)

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