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OpenStudy (anonymous):
if pq=12 and (p+q)2=24, then find the value of p2+q2. The 2 are the square units
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OpenStudy (anonymous):
Use ^ for the power (p+q)^2 = p^2 + 2pq + q^2 = 24 p^2 + q^2 = 24 - 2pq pq = 12 Therefore p^2 + q^2 = 24 -24 = 0
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