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n^11/((n^5)) lol fail. how do you nest. and for this could you explain how to d othis. so i can do it on my own.. :)
IS (a,b) open on R2
?
use property: \[n ^{a}/n ^{b}= n ^{a-b}\]
ok. yea i was not sure what to do with the exponents.
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n^11/n^6=n^11-6=n^5
Can u tell me the answer of construct a component set of real numbers with a countable set of limit points
ummmmm no? i already got it
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