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Mathematics 22 Online
OpenStudy (anonymous):

how do you go from (a + 1/b)/(b + 1/a) to a/b?

OpenStudy (anonymous):

this equal to \[[(ab+1)/b]/[(ab+1)/a]\] multiply below and above with ab yields \[[(ab+1)a]/[(ab+1)b]\] cancel out (ab+1), u wil get a/b

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