Question

Find three consecutive integers such that the sum of twice the smallest and three times the largest is 126.

Answer 1

24 25 26

Answer 2

you have been given that 2a+3(a+2)=126
so, simply solve for a: -
expand the brackets, 2a+3a+6=126
collect like terms; 5a=120
divide by 5; a=24
this gives the first number in the sequence so then a+1=25 and a+2=26

Answer 3

Thanks!