A manufacturer inspects 500 personal video players and finds that 496 of them have no defects. The manufacturer sent a shipment of 2000 video players to a distributor. Predict the number of players in the shipment that are likely to have no defects.
A. 16
B. 1840
C. 496
D. 1984
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OpenStudy (anonymous):
496/500=.992
1-.992=.008
2000*.008=16
OpenStudy (anonymous):
woah
OpenStudy (anonymous):
do you know what i did?
OpenStudy (anonymous):
not at all
OpenStudy (anonymous):
16 is the number that defected. it should be 2000-16=1984
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OpenStudy (anonymous):
r we gonna hav a debate here
OpenStudy (anonymous):
first i found the percentage that have no defects (496/500)
then i subtracted i from it to find the percentage with defects (1-.992)
then multiply by the 2000
OpenStudy (anonymous):
lol..no sweetie. juz wanna tell u the answer. so better i dont answer ur questions.
OpenStudy (anonymous):
wait anfar is right i found the defects for 2000
OpenStudy (anonymous):
sorry
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