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log(x-3)-log3=1
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i know if there was log on the right side of the equal sign i just solve the equation
When you say log are you referring to base 10 or base e, also known as ln
logx-logy=log(x/y)
log{(x-3)/3}=1
I'm assuming it is base 10
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write 10^[log{(x-3)/3}]=10^1 => (x-3)/3=10 I'm assuming you can finish the rest
Log(x-3) = 1 + log3 \[10^{\log(x-3)} = 10^{1 + \log3}\] \[x - 3 = 30\] \[x = 33\]
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