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if f(x)= x-2 / x+1 , then f(n+1) equals what?
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f(n+1) = (n+1) - 2 ------- (n+1) + 1
might wanna simplify it...
\[(n(n+3)/(n+1)\]
??? you sure bout that ???
i chose n+2-2/ n+1+1 and it was wrong so i think it is the other one
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n+2-2 ?? that aint right (n+1) - 2
Just simply replace x with n f(n) = n-2/n+1 f(n+1)= n-1/n+2
Sorry. I used the incorrect function syntax in a program solver. \[((n+1)-2)/((n+1)+1)=(n-1)/(n+2)\] amistre64 and sstarcia are correct.
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