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OpenStudy (anonymous):
what is c^-1 (x) given c (x) =x^3-5 ?
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OpenStudy (anonymous):
it is the same as the previous one try to solve it and show me ur work =)
OpenStudy (amistre64):
the inverse of c(x); c(x)=y replace "x" with "y" and solve for "x"
OpenStudy (amistre64):
x = y^3 - 5 x+5 = y^3 3root(x+5) = y c^-1(x) = 3root(x+5)
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