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does anyone know how to gernerate the equation of a circle with endpoints of diameter at (-3,5) and (7,11)
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ya. just use your equation of a circle
ok i got (x-2)^2 + (y-8)^2= and then what?
(x+3)(x-7) + (y-5)(y-11) = 0
whoa thanks dude i thought u didn't like me lol
how did you get that?
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sorry , if you felt i that
haha its ok
equation of any circle if the end points of its diameter are (a,b) and (p,q) is (x-a)(x-p) + (y-b)(y-q) =0
ok thank you
can you try to help with mine?
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sorry worm, i can't
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