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find three consecutive multiples of 15 such that twice their sum is 360
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so we know that those 3 consecutive numbers equal 180, so those 3 numbers are 45, 60, and 75
yeah i know i dont know how to explain
If 15x is the first number, then the other two are 15(x+1) and 15(x+2)....then 2[15x + 15(x+1) + 15(x+2)] =360....solve and u'll get x=3....sub into the expressions repr the three numbers...u'll get 45, 60 and 75
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