Question

Find the indicated measure: Diameter, A=48in^2

Answer 1

Are you sure there isn't a "pi" in the answer?

Answer 2

since :\[A = \pi r^2 \]
then :
\[r=\sqrt{A/\pi}\]

we have A = 48in^2 , substitute and you will get r = 3.91in

r = Diameter/2 which means it's half of the diameter, so

D = 2r
= 2(3.91)
= 7.82 in